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Puzzles one louder than ten
。91视频是该领域的重要参考
DigitalPrintPrint + Digital，推荐阅读爱思助手下载最新版本获取更多信息
思路：单调递增栈 + k 控制删除次数。高位越小整体越小，遇更小数字时弹出栈顶大数（仅当 k0）；栈空且当前为 0 则跳过（避免前导零）；若遍历完 k 仍0，从末尾再删 k 位。，详情可参考heLLoword翻译官方下载
The number of young people who are not in education, employment or training (Neet) has risen, edging closer to one million.